Electronics

RL Time Constant Calculator

Calculate RL time constant, current-rise milestones, and equivalent cutoff frequency from inductance and resistance.

Time Constant

100 us

5 Tau Settling

500 us

Cutoff Frequency

1,591.549 Hz

After 1 Tau

63.2%

RL Timing and the Slow Rise of Current

Current Cannot Jump Through an Inductor

An inductor resists changes in current. That single fact explains flyback spikes, relay coil delays, motor winding behavior, and many switching-power quirks. In an RL circuit, the time constant tells how quickly current approaches its final value after a voltage step. The equation is different from an RC circuit, but the exponential idea is familiar: after one time constant, current has moved about 63 percent of the way toward steady state.

Resistance Sets the Final Current

The resistor sets the final current, and the inductor sets how quickly that current can change. At the instant a voltage is applied, an ideal inductor current cannot jump. The applied voltage initially appears mostly across the inductor. As current rises, the resistor drop grows, leaving less voltage across the inductor, so the rate of current change slows. The time constant is inductance divided by resistance. More inductance means slower current change. More resistance means a faster settling time and lower final current.

A Ten-Millihenry Coil

The working equation is Tau = L / R. A first-order RL current reaches about 63.2% after one tau.

Convert inductance from millihenries to henries, then divide by resistance in ohms. A 10 mH inductor with 100 ohms gives 0.0001 seconds, or 100 microseconds. Five time constants is about 500 microseconds. The equivalent first-order cutoff frequency is 1 over 2 pi tau. If the answer feels wrong, check the inductance unit. Millihenries, microhenries, and henries are easy to mix, and a factor of 1000 changes the timing story completely.

Model limit: Assumes an ideal first-order resistor-inductor network.

Following the First Five Time Constants

A 10 mH inductor in series with 100 Ω has time constant L/R = 0.010/100 = 100 µs. Driven by a 5 V step, its ideal final current is 50 mA. After one time constant current reaches 63.2 percent, about 31.6 mA; after three it reaches 47.5 mA, and after five it is about 49.7 mA. The associated corner frequency R/(2πL) is 1.59 kHz. Voltage across the inductor starts near 5 V and decays as current builds.

If the inductor winding has 20 Ω DC resistance, total series resistance is 120 Ω. The time constant falls to 83.3 µs and final current falls to 41.7 mA. Omitting winding resistance therefore makes both timing and current wrong in different directions. When the source opens, the inductor tries to preserve current and can create a large voltage; a flyback path changes the decay time and protects the switch. Measure current through a small shunt and include the shunt resistance in the model used for comparison.

Coil Resistance Belongs in R

Inductance should represent the winding or component at the current level of interest. Magnetic cores can saturate, and inductance may fall as current rises. Resistance should include winding resistance and any series resistance in the current path. If a driver has current limiting, PWM control, diode clamps, or active recirculation, the effective voltage and resistance during decay may differ from the simple rise case. The calculator models the first-order RL path, so the entered resistance must match that path.

Opening the Circuit Safely

A common mistake is using the coil resistance to predict current rise while ignoring the supply voltage and driver behavior. The time constant describes the shape, but final current still depends on voltage and resistance. Another mistake is assuming current decay has the same time constant as current rise. A flyback diode, zener clamp, H-bridge slow-decay mode, or active brake can change the decay path. The calculator does not model switching detail; it gives the clean RL timing baseline.

The time constant tells whether a winding current can follow a command. In a relay, a long time constant can delay pull-in or release. In a stepper motor, winding inductance limits current rise at high step rates. In a solenoid, force depends on current, so timing affects mechanical response. The cutoff frequency is useful when the RL network behaves as a filter or when comparing electrical response with PWM frequency. If the PWM period is short compared with tau, current ripple is smaller.

Comparing Scope Data with the Model

Use the calculator when selecting relay drivers, sizing current-control loops, reviewing motor winding data, or estimating inductor current response. On the bench, measure current with a current probe or sense resistor and compare the 63 percent rise time with tau. If the measured curve differs, check saturation, supply limits, driver voltage drop, diode path, and parasitic resistance. RL circuits are simple on paper, but magnetic components often bring real-world behavior with them.

A good RL note records inductance, resistance, current path, supply or clamp behavior, tau, five-tau time, and the mechanical or switching event tied to that timing. The calculator is not a magnetic design program, but it teaches the first question: how fast can current change? Once that answer is visible, relay delays, motor torque loss at speed, and inductor ripple become easier to reason about.

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